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He length of a rectangle is 12 in. And the perimeter is 56 in. Find the width of the rectangle. A. 21 in. B. 22 in. C. 32 in. D. 16 in.

User Vovchisko
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The formula of a perimeter of rectangle:

P = 2(w + l)

We have l = 12 in and P = 56 in.

Substitute:

2(w + 12) = 56 use distributive property

(2)(w) + (2)(12) = 56

2w + 24 = 56 subtract 24 from both sides

2w = 32 divide both sides by 2

w = 16

Answer: D. 16 in.

User Yarbelk
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