2 Answers

Sukhmeet Sethi · Answer 1 · 2022-07-12T21:24:59+0000

Explanation:

$\tt{2 {x}^(2) + 5x - 3 = 0}$

⇢
$\sf{2 {x}^(2) + 5x + ( - 3) = 0}$

Here , a = 2 , b = 5 & c = -3 {a is the coefficient of x² , b is the coefficient of x and c is the constant term }

Now ,

$\tt{x = \frac{ - b± \sqrt{ {b}^(2) - 4ac } }{2a} }$

⇢
$\tt{x = \frac{ - 5± \sqrt{ {5}^(2) - 4 * 2 * ( - 3) } }{2 * 2} }$

⇢
$\sf{ x= ( - 5±7)/(4) }$

Taking positive ( + ) sign :

⇝
$\tt{x = ( - 5 + 7)/(4) = (1)/(2)}$

Taking negative ( - ) sign :

⇝
$\tt{x = ( - 5 - 7)/(4) = - 3}$

$\purple{ \boxed{ \boxed{ \tt{⤑ \: Our \: final \: answer : \boxed{ \underline{ \tt{x = (1)/(2) , \: - 3}}}}}}}$

Hope I helped ! ツ

Have a wonderful day / night♡

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