Question

Julia's frogs are 2/5 of the amount of Rimma's frogs. If Rimma gives 1 /2 of her frogs to Julia, what will be the ratio of Julia's frogs to Rimma's frogs?

Answer 1

Find out the what will be the ratio of Julia's frogs to Rimma's frogs.

To proof

let us assume that the amount of Rimma's frogs = x

`Julia's\ frogs\ are\ (2)/(5)\ of\ the\ amount\ of\ Rimma's\ frogs.`

than the

Julia's frogs becomes

`=(2x)/(5)`

As given

`If\ Rimma\ gives\ (1)/(2)\ of\ her\ frogs\ to\ Julia,`

than the

Rimma's frogs becomes

`=x- (x)/(2) \\= (x)/(2)`

Julia's frogs becomes

`= (2x)/(5)+ (1x)/(2) \\ =(9x)/(10)`

Than the ratio of Julia's frogs to Rimma's frogs

`(Julia's\ frogs)/( Rimma's frogs) = (9x*2)/(10* x)`

thus

`=(9)/(5)`

Hence proved

Answer 2

9:5

Explanation:

Rimma = x

Julia = 2/5 x

Rimma gives away 1/2 of her frogs.

Now Rimma has 1/2x and Julia has 2/5x + 1/2x=4/10x +5/10x =9/10x

Ratios are fractions so put Julia's on top of Rimma's and simplify.

(9/10 x) / (1/2x)

The x's will cancel. Invert the second fraction and multiply.

(9/10)*(2/1) = 18/10= 9/5

Ratio of Julia's frogs to Rimma's frogs is 9:5.