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If M = 624,619,430,000 find the smallest power of 10 that will exceed M

1 Answer

1 vote

Answer-

The smallest power of 10 that will exceed M is 12.

Solution-

Here,


M = 624,619,430,000

Writing this number in scientific notation,


M = 624,619,430,000 = 6.24619430* 10^(11)

As the given number is the order of 11, so the next order will be greater than M.

So the next order of 10 will be,


=10^(11+1)


=10^(12)

Therefore, the smallest power of 10 that will exceed M is 12.

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