Question

if the temperature remains constant and the initial pressure is 101.3 kPa then what is the new pressure reading when the volume is doubled

Answer 1

The pressure will decrease by half.

Step-by-step explanation:

Data Given:

P₁ = 101.3 kPa

V₁ = X

V₂ = 2X

P₂ = ??

Let us suppose the initial volume is 5 L and the final volume when doubled is 10 L. Then According to Boyle's Law, " The Volume of a given mass of gas at constant temperature is inversely proportional to the applied Pressure". Mathematically the initial and final states of gas are given as,

P₁ V₁ = P₂ V₂ ----------- (1)

Solving equation 1 for P₂,

P₂ = P₁ V₁ ÷ V₂

Putting values,

P₂ = (101.3 kPa × 5 L) ÷ 10 L

P₂ = 50.65 kPa

Result:

As the volume is doubled, the pressure is decreased from 101.3 kPa to 50.65 kPa or it has decreased by half.