Question

What is the perimeter, in feet, of a rectangle whose length is four times its width

which is 8 feet?

Answer 1

Answer is 80 feet

Step by step

We know perimeter is
P = 2L + 2W

We know L = 4W
We know W = 8

Substitute these into our formula and solve

P = 2(4 x 8) + 2(8)

P = 2(32) + 16

P = 64 + 16

P = 80 ft

Problem solved!