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How many atoms are in 8.00 moles of potassium chromate?​

2 Answers

4 votes

Answer:

481.6x10^23

Step-by-step explanation:

User Soonts
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6.9k points
3 votes

Answer:


\boxed {\boxed {\sf About \ 4.82 *10^(24) \ atoms \ K_2CrO_4}}

Step-by-step explanation:

To convert from moles to atoms, Avogadro's Number must be used.


  • 6.022*10^(23)

This number tells us how many particles (atoms, molecules, ions. etc.) in 1 mole of a substance. In this case, it is atoms of potassium chromate (K₂CrO₄) in 1 mole.


6.022*10^(23) \ atoms \ K_2CrO_4 / 1 \ mol \ K_2CrO_4

Use this number as a fraction.


(6.022*10^(23) \ atoms \ K_2CrO_4)/(1 \ mol \ K_2CrO_4)

Multiply by the given number of moles (8.00).


8.00 \ mol \ K_2CrO_4 *(6.022*10^(23) \ atoms \ K_2CrO_4)/(1 \ mol \ K_2CrO_4)

The moles of potassium chromate will cancel.


8.00 *(6.022*10^(23) \ atoms \ K_2CrO_4)/(1)

The denominator of 1 can be ignored.


8.00 *(6.022 *10^(23) \ atoms \ K_2CrO_4)

Multiply.


4.8176*10^(24) \ atoms \ K_2CrO_4

The original measurement of moles (8.00) has 3 significant figures, so we must round our answer to 3 sig figs.

For the number we calculated, that is the hundredth place. The 7 in the thousandth place tells us to round the 1 up to a 2.


4.82 *10^(24) \ atoms \ K_2CrO_4

There are about 4.82* 10²⁴ atoms of potassium chromate in 8.00 moles.

User Eugene Khyst
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7.8k points