Answer:
The equation of the line that passes through the points (7,-8) and (2, -8) is
![\mathbf{y=-8}](https://img.qammunity.org/2022/formulas/mathematics/college/uu00p3z8h1wh1ehf7xyop6ov27k5wv69jn.png)
Explanation:
We need to write the equation of the line that passes through the points (7,-8) and (2, -8).
We need to write answer in fully reduced point-slope form, unless it is a vertical or horizontal line.
The general equation of point-slope form is:
![y-y_1=m(x-x_1)](https://img.qammunity.org/2022/formulas/mathematics/middle-school/vtillwnvtmv4154m1gj6eh3pnty0mf96g6.png)
where m is slope of the line.
To find the slope, we can use formula:
![Slope=(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2022/formulas/mathematics/high-school/74v13u5xocmslbx1zls2px1jkbzuf7apjd.png)
We have
![x_1=7,y_1=-8,x_2=2, y_2=-8](https://img.qammunity.org/2022/formulas/mathematics/college/4yaiqp5kai2vn3xjwaqht04qd3p7yo6mg5.png)
Putting values and finding slope:
![Slope=(y_2-y_1)/(x_2-x_1)\\Slope=(-8-(-8))/(2-7)\\Slope=(-8+8)/(-5)\\Slope=(0)/(-5)\\Slope=0](https://img.qammunity.org/2022/formulas/mathematics/college/zori8685td279vt3zslao15c6j6aew6o2o.png)
So, we find the slope : m = 0
Now, using the point (7,-8) and slope m =0, the required equation is:
![y-y_1=m(x-x_1)\\y-(-8)=0(x-7)\\y+8=0\\y=-8](https://img.qammunity.org/2022/formulas/mathematics/college/o0p19dz23z5m3cxmzr1ullnz6ivlnacv3t.png)
So, the equation of the line that passes through the points (7,-8) and (2, -8) is
![\mathbf{y=-8}](https://img.qammunity.org/2022/formulas/mathematics/college/uu00p3z8h1wh1ehf7xyop6ov27k5wv69jn.png)