Question

How much methanol (CH3OH, in grams) can be formed from 42.2 kg of hydrogen? Assume excess CO.

CO(g) + 2H2(g) → CH3OH(g)

Answer 1

335 000 g

Step-by-step explanation:

We know that we will need a chemical equation with masses and molar masses, so let’s start by gathering all the information in one place.

`M_(r)`: 2.016 32.04

CO + 2H₂ ⟶ CH₃OH

Mass/kg: 42.2

1. Use the molar mass of H₂ to calculate the moles of H₂.

Note: 1 g/mol ≡ 1 kg/kmol

`\text{Moles of H}_(2) = \text{42.2 kg}* \frac{\text{1 kmol} }{\text{2.016 kg}}= \text{20.93 kmol}`

2. Use the molar ratio of CH₃OH:H₂ to calculate the moles of CH₃OH.

`\text{Moles of CH$_(3)$OH} = \text{20.93 kmol H}_(2) * \frac{\text{1 kmol CH$_(3)$OH}}{\text{2 kmol H}_(2)} = \text{10.47 kmol CH$_(3)$OH}`

3.Use the molar mass of CH₃OH to calculate the mass of CH₃OH.

`\text{Mass of CH$_(3)$OH} = \text{10.47 kmol CH$_(3)$OH}* \frac{\text{32.04 kg CH$_(3)$OH} }{\text{1 kmol CH$_(3)$OH }}= \text{335 kg CH$_(3)$OH}`

`= \text{335 000 g CH$_(3)$OH}`