Question

Solve the equation for 0° ≤ x ≤ 90°. Round to the nearest degree. tan^2 B = 4

Answer 1

`B=63\degree`

Step-by-step explanation

We want to solve the trigonometric equation;

`tan^2(B)=4`, where
`0\degree \le B \le 90\degree`.

Taking square root of both sides gives,

`tan(B)=\pm √(4)`

`tan(B)=\pm 2`

Since B is in the first quadrant, we proceed with;

`tan(B)=2`, because the tangent ratio is positive in the first quadrant.

`\Rightarrow B =arctan(2)`

`\Rightarrow B =63.43\degree`.

Correct to the nearest degree,

`B =63\degree`