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A space station has a radius of 200m.

A. What period of rotation is needed to provide an artificial gravity of g at the rim?

User Speeder
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1 Answer

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For artificial gravity the the position of rim we have to rotate the space station

Due to rotation it will experience centripetal acceleration at the position of rim

Now in order to experience this acceleration to be same as gravity we can say centripetal acceleration must be equal to gravity here


a_c = g

as we know that centripetal acceleration is given as


a_c = w^2R


a_c = w^2*200 = g


w^2* 200 = 9.8


w = \sqrt{(9.8)/(200)}


w = 0.22 rad/s

now we know that angular frequency will be related to time period as


T = (2\pi)/(w)


T = (2\pi)/(0.22)


T = 28.4 s

so it will rotated by time period T = 28.4 s

User Dhruvin
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