Question

HELP PLEASE !!! If anybody sees this can you help me ASAP

Answer 1

`g(x)=(x-3)^(2) +2` has the same shape as the parabola
`g(x)=x^(2)` but with vertex shifted to (3, 2).

The vertex of the parabola
`(y-k)^(2) =4a(x-h)` is (h, k).

Equation of the given graph is
`g(x) = (x-3)^(2) +2`

Subtract 2 from both sides.

`g(x)-2=(x-3)^(2)`

Hence, its vertex is at (3, 2).

Please find the attached graph.