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What is the area of a rectangle with vertices at ​ (−4, 0) ​, ​ (−3, 1) ​ , (0, −2) , and (−1, −3) ?

User Tormod
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2 Answers

1 vote

(4,0)( -3,1)


1-0. 1+0=0

-3-4 -3+4=7

Y=7

User Headbanger
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2 votes

Answer:

6 square units

Explanation:

Graph this rectangle. Doing so shows that it's located in Quadrants II and III. The length is the distance between (-3,1) and (0, -2): √(9+9), or 3√2

The width is the distance between (-4,0) and (-3,1), or √(1+1) = √2.

The area is (length)(width) = 3√2 * √2 = 3(2) = 6 square units.

User Yuushi
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