Question

a series circuit contains two devices one with a resistance of 10 ohms and one with a resistance of 4 ohms if the generator supplies a voteage of 42 v what is the magnitude of the current?

Answer 1

Current(I) = Voltage/Resistance

= 42/(10+ 4)

= 42/14

Current = 3 A

Answer 2

i = 3 A

Step-by-step explanation:

When two or more resistances are connected in series then the total effective resistance is given as

`R_(eq) = R_1 + R_2`

now we have

`R_(eq) = 10\: ohm + 4\: ohm`

`R_(eq) = 14\: ohm`

now from ohm's law we know that

`V = i R`

here we know that

V = 42 volts

R = 14 ohm

now from above equation

`42 = i * 14`

`i = 3 A`