Answer:
Option B.
Explanation:
From the table if Rohit draws a graph to define the sales of the pumpkins, he will take weight on x - axis and price on y-axis.
Increase in sales of pumpkins will be defined by increase in price of the pumpkin with the increase of weight.
Or Slope of the graph =
![\frac{\text{Increase in price}}{\text{Increase in weight}}](https://img.qammunity.org/2019/formulas/mathematics/middle-school/fs39mh2q6sab5risjd8jggwf00g0081686.png)
=
![((12-6))/((8-4))](https://img.qammunity.org/2019/formulas/mathematics/middle-school/f5msdbi32y265fkj82n8zw0fqp6g9w2rwb.png)
=
![(6)/(4)](https://img.qammunity.org/2019/formulas/mathematics/high-school/cgbt43ktq3mvbrjdfod78tobhgxpm8ip72.png)
= $1.5
Rohit finds that for every increase of 1 pound price increases by $1.5.
Therefore, option B. is the correct option.