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Why are there two solutions for the equation |6 + y| = 2? Explain.

User Murugesh
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2 Answers

4 votes

Answer:

Here is what I wrote:

There are two solutions for |6+y|=2, -8 and -4.

This is because |6+(-8)| and |6+(-4)| both equal 2.

The absolute value is the distance to zero on a number line.

If one were to graph the equation there would be a line with two different directions to determine distance from 0.

User Artem Zinnatullin
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6.3k points
7 votes


Solution, \left|6+y\right|=2\quad :\quad y=-8\quad \mathrm{or}\quad \:y=-4


Steps:


|f\left(y\right)|=a\quad \Rightarrow \:f\left(y\right)=-a\quad \mathrm{or}\quad \:f\left(y\right)=a, 6+y=-2\quad \quad \mathrm{or}\quad \:\quad \:6+y=2


6+y=-2\quad :\quad y=-8,\\6+y=-2,\\\mathrm{Subtract\:}6\mathrm{\:from\:both\:sides}, 6+y-6=-2-6,\\\mathrm{Simplify}, y=-8


6+y=2\quad :\quad y=-4,\\6+y=2,\\\mathrm{Subtract\:}6\mathrm{\:from\:both\:sides},6+y-6=2-6\\\mathrm{Simplify},y=-4


\mathrm{Combine\:the\:ranges}, y=-8\quad \mathrm{or}\quad \:y=-4


\mathrm{The\:Correct\:Answer\:is\:Because\:of\:the\:absolute\:value,\:It\:could\:be\:Positive\:or\:negative.}


\mathrm{Hope\:This\:Helps!!!}


\mathrm{-Austint1414}

User Amomum
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6.9k points