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What is the value of n so that the expression x2 11x n is a perfect square trinomial

User Atorscho
by
6.8k points

1 Answer

2 votes

Answer:


n=(121)/(4)

Step-by-step explanation:

Since we know that perfect square trinomial formula states that any trinomial of the form
ax^(2) +bx+c is said to a perfect square if it satisfies the condition
b^(2) =4ac.

We are given an expression
x^(2) ?11x ?n and asked to find value of n for expression to be a perfect square trinomial .

Let us compare our expression with perfect square trinomial formula.

We can see that a=1, b=11 and c=n.

Let us find value of n by substituting our given values in
b^(2) =4ac.


11^(2) =4*1*n


121 =4n.


n=(121)/(4)

Therefore,
n=(121)/(4) will make the expression
x^(2) ?11x ?n a perfect square trinomial.




User Gall
by
6.5k points
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