Question

An airplane accelerates down a runway at 3.20 m/s2 for 32.8 s until is finally lifts off the ground. What is the distance traveled before takeoff?

Answer 1

1721 m/s

Step-by-step explanation:

We can solve the problem by using the following SUVAT equation:

`S=(1)/(2)at^2`

where S is the distance traveled, a is the acceleration of the plane and t is the time.

In this problem, a=3.20 m/s^2 and t=32.8 s, so we can find the distance traveled by the plane by substituting these numbers into the equation:

`S=(1)/(2)(3.20 m/s^2)(32.8 s)^2=1721 m`