Answer:probability of an event E,
P(E)=No. of favourable outcomes total no. of outcomes
P(1)=420=15=0.20
P(2)=620=310=0.30
P(3)=220=110=0.10
P(4)=620=310=0.30
P(5)=220=110=0.10
Explanation:
6.7m questions
8.9m answers