Question

HELP ME WITH MY MATH ASSIGNMENT, WILL GIVE ANYTHING, DUE TOMORROW! :(

Answer 1

Explanation:

Question 2) Answer

Use Arithmetic Series Formulas:

a) Nth term = F + (N - 1) x D, where F=First term, N=Number of terms, D=Common difference

6th row = 23 + (6 - 1) x -3

= 23 + (5) x -3

= 23 + (-15)

= 8 - number of boxes in the top row.

b) Sum = N/2[2F + (N - 1) x D]

= 6/2[2*23 + (6 - 1) x -3]

= 3 [46 + (5) x -3 ]

= 3 [46 + -15 ]

= 3 [ 31 ]

= 93 - total number of boxes in the entire display.

Question 3) Answer

Sum of the 8 first terms of the geometric progression with the first term 50 and the common ratio of 2:

=50 + 5*2 + 50*2^2 + . . . + 50*2^7

= 50*(1 + 2 + 2^2 + . . . + 2^7) = 50*(2^8-1)

= 50*(256-1) = 50*255

= 12750 Answer

I am also attached the solved question of this assignment please check and enjoy. Thanks

Answer 2

Answer is 225.

We have to find the sum of 15 terms of the series

sigma 1 to 15 (2n-1)

This can be split as per summation terms as

sigma 2n - sigma 1

sigma 2n can again be simplified by taking 2 outside

sigma 2n= 2 times sum of natural numbers of 1 to 15

= 2(15)(16)/2= 240

sigma 1= 1+1+...15 times= 15

Hence final answer is

= 2 times sigma n - (n) = 240-15 = 225.

Explanation: