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How do you find the quadratic function with vertex (-2,5) and point (0,9)?

User Mdryden
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1 Answer

3 votes

Answer: y = (x +2)² + 5

Explanation:

y = a(x - h)² + k where "a" is the leading coefficient and (h, k) is the vertex

Since we don't know "a", we need to plug in the point (x, y) and the vertex (h, k) to solve for "a": (x, y) = (0, 9) and (h, k) = (-2, 5)

y = a(x - h)² + k

9 = a(0 - (-2))² + 5

9 = a(0 + 2)² + 5

9 = a(2)² + 5

-5 -5

4 = a(4)

÷4 ÷4

1 = a

Next, plug in "a" and the vertex (h, k):

y = a(x - h)² + k

y = 1(x +2)² + 5

y = (x +2)² + 5


User Ximyu
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