Question

What is the solution of the equation when solved over the complex numbers?

x^2+27=0

Thanks!

Answer 1

x = ± 3i√3

given x² + 27 = 0 (subtract 27 from both sides )

x² = - 27 ( take the square root of both sides )

x = ±
`√(-27)` = ± √(9 × 3 × -1 ) ← (i = √-1 )

= ± (√9 × √3 ×√-1 ) = ±3i√3

Answer 2

Try this option:

x²+27=0;

`(x+√(-27))(x- √(-27))=0; \ => \ \left[\begin{array}{ccc}x=3 √(3)i\\x=-3 √(3)i \end{array}\right`