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6x+5y+2z=41 4x-10z=-10 -x-2y+2z=-1
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1 vote
6x+5y+2z=41
4x-10z=-10
-x-2y+2z=-1

User Hilary Park
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1 Answer

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\left[x \right] = \left[ \frac{5\,y}{158}+\frac{6\,z}{79}\right][x]=[​158​​5y​​+​79​​6z​​] totally answer
User Kevin Dolan
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