Question

The drama club sold bags of candy and cookies to raise money for the spring show. Bags of candy cost $5.50 and bags of cookies cost $3.50, and the sales total was $53.50. There were 5 more bags of cookies sold than candy. Find the number of bags of candy and cookies sold by the drama club.

Answer 1

Let's assume

the number of bags of candy =x

the number of bags of cookies =y

There were 5 more bags of cookies sold than candy

so, we get

`y=x+5`

Bags of candy cost $5.50

so, total cost of candy is

`=5.50x`

bags of cookies cost $3.50

so, total cost of cookies is

`=3.50y`

so,

total cost = (total cost of candy)+(total cost of cookies)

we get

total cost =5.50x+3.50y

so, we can plug

`5.50x+3.50y=53.50`

now, we can plug y

`5.50x+3.50(x+5)=53.50`

`5.5x\cdot \:10+3.5\left(x+5\right)\cdot \:10=53.5\cdot \:10`

`55x+35\left(x+5\right)=535`

`55x+35x+175=535`

`90x+175=535`

`90x+175-175=535-175`

`90x=360`

`x=4`

now, we can find y

`y=x+5`

`y=4+5`

`y=9`

so,

the number of bags of candy =4

the number of bags of cookies =9............Answer