Question

A jet plane travels from Calgary to Winnipeg ,a distance of 1385m, in 2h and 45 mins. Determine the speed of the jet plane in m/s

Answer 1

The speed of the jet plane from Calgary to Winnipeg is calculated by converting the travel time to seconds and dividing the given distance by this time, resulting in a speed of 0.14 m/s.

Step-by-step explanation:

To calculate the speed of the jet plane in meters per second (m/s), you need to convert the travel time from hours and minutes to seconds and then use the formula for speed, which is distance divided by time. The given distance is 1385 meters (m), and the time is 2 hours and 45 minutes. First, convert 2 hours and 45 minutes to seconds:

2 hours are 7200 seconds (2 × 3600 s/h) and 45 minutes are 2700 seconds (45 × 60 s/min), totaling 9900 seconds.

The speed can then be calculated as follows:

Speed = Distance ÷ Time = 1385 m ÷ 9900 s = 0.14 m/s (rounded to two decimal places).

Therefore, the jet plane's speed is 0.14 m/s when traveling from Calgary to Winnipeg.

Answer 2

309.5752 m/s.

First, split the "1385 m" in half, because it takes 2 hours to get that far. So this way, we're turning it into mph (miles per an hour). (If m = miles)

Secondly, turn the mph (miles per an hour) into m/s.

Third, just some calculation, and you're done.