268,315 views
37 votes
37 votes
5. A ball is thrown up in the air with an initial velocity of 11.4 m/s. What is the maximum height in the air the ball will reach?​

User Rob Willis
by
2.8k points

1 Answer

23 votes
23 votes

Answer:

6.50m

Step-by-step explanation:

Vf=0

Vi=11.4

g=-10(against the gravity)

D=x?

Vf²=vi²+2ad

0²=11.4²+2(-10)d

0=129.96+-20d

-129.96=-20d

-129.96/-20=d

D=6.50m

User TSR
by
2.8k points