Question

A conveyor belt takes products from the ground to the storage loft of a building. The belt makes an angle of 52 degrees with the wall of the building, and the loft door is 27 feet above the ground. Approximately how far does the belt travel from the ground to the loft?

Answer 1

Answer: 43.85 feet.

Explanation:

1. You can draw a rigth triangle, as you can see in the figure attached. Where
`x` is the distance traveled from the ground to the loft.

2. Then, to solve this problem you should follow the proccedure shown below:

`cos\alpha=(adjacent)/(hypotenuse)`

Where:

`\alpha=52`°

`adjacent=27`

`hypotenuse=x`

3. Substitute the values. Therefore, the result is:

`cos(52)=(27)/(x)\\x=(27)/(cos(52))\\x=43.85ft`