Question

Simplify completely 4x^2-7x+3 / x^2 + 5x-6

A) 4x+ 1 / x-1
B) 4x-1 / x+6
C) 4x+3 / x-1
D) 4x-3 / x+6

ASAP PLEASE!

Answer 1

Your answer is D.

`(4x-3)/(x+6)`

Explanation:

First, you have to factor by grouping.

Next, factor using AC method.

Last, cancel the common factor.

Now all you do is rewrite the expression.

Answer 2

D)
`\frac{4x-3} {x+6}`

Explanation:

First we have to factorize and then cancel the like terms.

Given,

`\frac{4x^2-7x+3} {x^(2)+5x-6}\\=\frac{4x^2-3x-4x+3} {x^(2)+6x-x-6}\\=\frac{x(4x-3)-1(4x-3)} {x(x+6)-1(x+6)}\\=\frac{(4x-3)(x-1)} {(x+6)(x-1)}`

Now, we got the like term (x-1).

Canceling this like term we get

`\frac{(4x-3)(x-1)} {(x+6)(x-1)}=\frac{4x-3} {x+6}`