Answer:
The correct answer is: Angle ∠CBD and angle ∠GFH
Explanation:
In ΔBCD ≅ ΔFGH
CB ≅ GF
BD ≅ FH
In ΔBCD ,angle between BD and CB is ∠CBD.
In ΔFGH ,angle between GF and FH is ∠GFH.
Angles which are used to show the SAS (side-angle-side) Postulate will be:
∠CBD ≅ ∠GFH