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How could you graph m(x)=logbase6(x+3)
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How could you graph m(x)=logbase6(x+3)

User Agftrading
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1 Answer

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f(x) + n - shift a graph of f n units up

f(x) - n - shift a graph of f n units down

f(x + n) - shift a graph of f n units left

f(x - n) - shift a graph of f n units right.


Plot the graph of
y=\log_6 x and shift it 3 units left.


How could you graph m(x)=logbase6(x+3)-example-1
User RowanC
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