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If (1/4)^2-y, =1 find the value of y

1 Answer

9 votes
First you need to do square 1/4, which equals 1/16

1/16 - y = 1

Then you subtract 1/16 on both sides

-y = 1 - 1/16

Then subtract 1/16 from 1

-y = 15/16

Then divide by -1 to make y positive

answer —-> y = -15/16

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