Answer:
(x - 5)( x + 2i)(x - 2i)
Explanation:
There might be a real root which is a factor of 20
Try 4:-
f(4) = 4^3 - 5*16 + 16 - 20 = -20 so its not 4
f(5) = 125 - 125 + 20 -20 = 0 so 5 is a root.
If 5 is a root then (x - 5) is a factor of the function:-
If we divide f(x) by x-5 we get
x^2 + 4
factor this- we get (x + 2i)(x - 2i)
so the factors are (x - 5)( x + 2i)(x - 2i)