Answer: The correct option is
(B)
![\left((1)/(2),1\right).](https://img.qammunity.org/2019/formulas/mathematics/high-school/i0k0tpg6vcdwem5l4uvppvww6ihsiutt0n.png)
Step-by-step explanation: We are given to select the point that does not lie on the graph of the following line :
![y=2x-2~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)](https://img.qammunity.org/2019/formulas/mathematics/high-school/us60l0uqf29m05hvtet920xam17b0y6awq.png)
Any point that does not lie on the graph of (i) will not satisfy the equation.
If
then
![R.H.S.=2x-2=2* \left(-(1)/(2)\right)-2=-1-2=-3=y=L.H.S.](https://img.qammunity.org/2019/formulas/mathematics/high-school/ej4se0m6icix5mh60qxed2ttchdugvuv83.png)
So, this option is NOT correct.
If
then
![R.H.S.=2x-2=2* \left((1)/(2)\right)-2=1-2=-1\\eq y=L.H.S.](https://img.qammunity.org/2019/formulas/mathematics/high-school/vnpyg6ii7cmeks9vf45dn3m3z9jx5225g8.png)
So, this option is correct.
If
then
![R.H.S.=2x-2=2* (-1)-2=-2-2=-4=y=L.H.S.](https://img.qammunity.org/2019/formulas/mathematics/high-school/tekaw3y3sft08d2i1ulbhohwtnjf8n4baf.png)
So, this option is NOT correct.
Thus, the correct option is (B).