Question

PLEASE HELP ME I HAVING TROUBLE

Answer 1

Answer: f(-6) =
`-(12)/(11)`, f(-4) =
`(8)/(9)`, f(4) =
`-(8)/(9)`, f(6) =
`(12)/(11)`

Explanation:

(-6, f(-6)) is an x,y coordinate. They are asking what the y-value is when you plug in -6 for x.

f(x) =
`(2x)/(x^(2)-25)`

f(-6) =
`(2(-6))/((-6)^(2)-25)`

=
`(-12)/(36-25)`

=
`-(12)/(11)`

f(-4) =
`(2(-4))/((-4)^(2)-25)`

=
`(-8)/(16-25)`

=
`(-8)/(-9)`

=
`(8)/(9)`

f(4) =
`(2(4))/((4)^(2)-25)`

=
`(8)/(16-25)`

=
`(8)/(-9)`

=
`-(8)/(9)`

f(6) =
`(2(6))/((6)^(2)-25)`

=
`(12)/(36-25)`

=
`(12)/(11)`