Answer:
b) The slope of line is 20
c) The equation in slope-intercept form is:
![\mathbf{y=20x}](https://img.qammunity.org/2022/formulas/mathematics/high-school/b8oypao5m2co1adalr1gohdc7yynzgfnb6.png)
d) i) she would have travelled 1480 m after 74 s
ii) It will take 125 s to travel 2.5 km
Explanation:
Part b: Slope of Line
Slope of line can be found using formula:
![Slope=(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2022/formulas/mathematics/high-school/74v13u5xocmslbx1zls2px1jkbzuf7apjd.png)
From the table we can take any two points and find the slope.
Looking at the graph, the time is x-axis and distance is y-axis
Let we take (0,0) and (8,160)
So, we have:
![x_1=0, y_1=0, x_2=8, y_2=160](https://img.qammunity.org/2022/formulas/mathematics/high-school/3qgv99ilwtpszd1xh472j3dbbqzvx1zc14.png)
Now finding Slope:
![Slope=(y_2-y_1)/(x_2-x_1)\\Slope=(160-0)/(8-0) \\Slope=(160)/(8)\\Slope=20](https://img.qammunity.org/2022/formulas/mathematics/high-school/fwj9ipp4uvenybgybg4c97f6ms8za2ms5u.png)
So, the slope of line is 20
Part c) Find the equation in slope-intercept form
The general equation of slope-intercept form is:
where m is slope and b is y-intercept
We have found slope, m = 20
We need to find y-intercept.
y-intercept can be found by putting x-axis (time) equal to zero and check what the y-axis (distance) is:
So, when x =0, y=0
So, y-intercept = 0
The equation will be:
![y=mx+b\\y=20x+0\\y=20x](https://img.qammunity.org/2022/formulas/mathematics/high-school/ai59k4whpm6w505akxd2sc28nuqc1takdi.png)
The equation in slope-intercept form is:
![\mathbf{y=20x}](https://img.qammunity.org/2022/formulas/mathematics/high-school/b8oypao5m2co1adalr1gohdc7yynzgfnb6.png)
Part d)
Part i) How far will she have travelled after 74 s
We are given time (x) = 74 s
We need to find distance i.e. y:
Using the equation:
![\mathbf{y=20x}](https://img.qammunity.org/2022/formulas/mathematics/high-school/b8oypao5m2co1adalr1gohdc7yynzgfnb6.png)
Put x = 74
![y=20x\\y=20(74)\\y=1480](https://img.qammunity.org/2022/formulas/mathematics/high-school/dm3iwqrjm7tpf8cs3t2qami6eytvxxz6bx.png)
So, she would have travelled 1480 m after 74 s
Part ii) How long will it take to travel 2.5 km
We are given distance (y) = 2.5 km
We need to find time i.e. x:
Using the equation:
![\mathbf{y=20x}](https://img.qammunity.org/2022/formulas/mathematics/high-school/b8oypao5m2co1adalr1gohdc7yynzgfnb6.png)
Since distance is given in meters but here it is in km
So converting 2.5 km into m
We know that 1 km = 1000m
So, 2.5 km = 2500 m
Now finding time:
![y=20x\\2500=20(x)\\x=(2500)/(20)\\x=125](https://img.qammunity.org/2022/formulas/mathematics/high-school/abkkl46488609mwta7wa86tl6iybtin18h.png)
So, It will take 125 s to travel 2.5 km