Question

Sarah lives 4miles west of Peter Amy Lives 6.5 miles south of petit how far is Sarahs House to Amy’s

Answer 1

Suppose Peter lives at O, i.e at the center in the middle of Four direction.

Distance from Sarah house to peter= 4 miles west of peter house=OS

Distance from Peter house to Amy= 6.5 miles south of peter house=OA

In right Δ S O A, ∠ O=90°

SA²= SO² + OA² → [By pythagoras theorem]

SA² =4² + (6.5)²

= 16+ 42.25

= 58.25

SA=√58.25=7.63 miles (approx)

Answer 2

Answer: Distance between Sarah's house and Amy's house is 7.6 miles.

Explanation:

Since we have given that

Distance at which Sarah lives west of Peter= 4 miles

Distance at which Amy lives south of Peter = 6.5 miles

Now, we need to find the distance between Sarah's house to Amy's house,

We'll use Pythagorus theorem,

`H^2=B^2+P^2\\H^2=4^2+6.5^2\\H^2=16+42.25\\H^2=58.25\\H=√(58.25)\\H=7.6`

So, Distance between Sarah's house and Amy's house is 7.6 miles.