Question

∣6x−7∣−8≥3

PLEASE HELP ASAP!!!!!

Answer 1

first step is to isolate the absolute value by adding 8 to each side

|6x-7| >= 11

now separate into 2 equations a positive and a negative (remembering to flip the inequality symbol for the negative)

6x-7>=11 6x-7<=-11

add 7 to each side

6x>=18 6x<=-4

divide by 6

x>=3 x<=-4/6

-2/3 >= x or 3<=x

Answer 2

`x \le -(2)/(3)` or
`x \ge 3`

Explanation:

`|6x - 7| - 8 \ge 3`

`|6x - 7| \ge 11`

`6x - 7 \le -11` or
`6x - 7 \ge 11`

`6x \le -4` or
`6x \ge 18`

`x \le (-4)/(6)` or
`x \ge (18)/(6)`

`x \le -(2)/(3)` or
`x \ge 3`