Question

How many hydrogen atoms are in 7.80 mol of ammonium sulfide?

Answer 1

Answer: There are
`3.75 * 10^(25)` number of H atoms in 7.80 mol of ammonium sulfide.

Step-by-step explanation:

The formula of ammonium sulfide is
`(NH_(4))_(2)S`.

There are 2 nitrogen atoms, 8 hydrogen atoms and 1 sulfur atom in one molecule of ammonium sulfide.

Calculate moles of hydrogen atoms as follows.

`8 * 7.80` = 62.4

According to Avogadro's number 1 mole contains
`6.022 * 10^(23) atoms`

Therefore, calculate number of H atoms as follows.

`62.4 * 6.022 * 10^(23)`

=
`375.77 * 10^(23)`

=
`3.75 * 10^(25)`

Thus, there are
`3.75 * 10^(25)` number of H atoms in 7.80 mol of ammonium sulfide.

Answer 2

The number of hydrogen atoms that are in 7.80 moles of ammonium sulfide are 3.756 x 10^25 atoms

calculation

Step 1: calculate the moles of H in (NH4)2S

since there are 8 atoms of H in (NH4)2S the moles of

H = 8 x7.80 = 62.4 mole

Step 2: use of Avogadro's law constant to determine the number of H atom

that is 1 mole = 6.02 x10^23 atoms

62.4 moles=? atoms

• cross multiplication

= [ 62.4 x 6.02 x10^23]/ 1 mole= 3.756 x10^25 atoms