Question

What is the approximate frequency of a photon having an energy 3.2 * 10^-24 J? (h = 6.6*10^-34 J*s)

a.) 48*10^9
b.) 2.1*10^-57
c.) 3.0*10^-58
d.) 2.1*10^-10

Answer 1

The Planck’s Equation states that

E = hv

E stands for energy measured in Joules

v stands for frequency measured in s^-1 or Hertz (Hz)- 1Hz .

h is Planck’s constant which is equivalent to 6.626x10-34 J.s

The Planck's equation states that the energy of a photon, is directly proportional to its frequency (v), by a constant factor (h).

Given:

E=3.2 * 10^-24 J

h= 6.626x10-34 J.s

Now we know that

E=hv

Thus substituting the given values we get

v=3.2 * 10^-24 /6.626x10-34

v=48 x 10^9 s^-1