Question

Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 5.90 moles of magnesium perchlorate, Mg(ClO4)2.

Express the number of moles of Mg, Cl, and O atoms numerically, separated by commas.

Answer 1

5.90, 11.8, 47.2

Step-by-step explanation:

Let’s remove the parentheses and write the formula as MgCl₂O₈.

We see that 1 mol Mg(ClO₄)₂ contains 1 mol Mg atoms, 2 mol Cl atoms, and 8 mol O atoms.

∴
`\text{Moles of Mg atoms} = \text{5.90 mol Mg(ClO}_(4))_(2) * \frac{\text{1 mol Mg atoms}} {\text{1 mol Mg(ClO}_(4))_(2)} = \text{5.90 mol Mg atoms}`

`\text{Moles of Cl atoms} = \text{5.90 mol Mg(ClO}_(4))_(2) * \frac{\text{2 mol Cl atoms}} {\text{1 mol Mg(ClO}_(4))_(2)} = \text{11.8 mol Cl atoms}`

`\text{Moles of O atoms} = \text{5.90 mol Mg(ClO}_(4))_(2) * \frac{\text{8 mol O atoms}} {\text{1 mol Mg(ClO}_(4))_(2)} = \text{47.2 mol O atoms}`

∴ Mg, Cl, O = 5.90, 11.8, 47.2