Question

the diagram below represents two beakers, each containing an ice cube and clear liquid. in beaker A the ice cube floats, and in beaker B the ice cube rest on the bottom. what is the most probable cause for the difference in behavior of the ice cube in the two beakers?

Answer 1

The most probable cause for the difference in behavior of the ice cube in the two beakers is the differences in density and buoyancy.

Step-by-step explanation:

The most probable cause for the difference in behavior of the ice cube in the two beakers is the differences in density and buoyancy.

In beaker A, the ice cube floats because it has a lower density than the surrounding liquid. The buoyant force exerted on the ice cube is greater than its weight, causing it to float.

In beaker B, the ice cube rests on the bottom because its density is higher than the surrounding liquid. The buoyant force acting on the ice cube is less than its weight, so it sinks to the bottom.

Answer 2

The density of the liquid in beaker B is less than the that of ice.

Explanation:

Ice will float if its mass is less than the mass of the liquid it displaces.

For example, the density of ice is less than that of water.

A 10 cm³ cube of ice has a mass of about 9 g, while the mass of 10 cm³ of water is 10 g. Thus, 9 g of ice displaces 10 g of water.

The denser water displaces the lighter ice and the ice floats to the top.

If the density of the liquid is less than that of water, say, 8 g/cm³, the ice will displace only 8 g of the liquid. The ice will sink.