Since they are consecutive, we can write that (x = the first number):
![(x)+(x+1)+(x+2)+(x+3)+(x+4)+(x+5)+(x+6) = 105](https://img.qammunity.org/2019/formulas/mathematics/middle-school/zu42mysohwxulo1rkbnk7gncdeh2qdla1s.png)
Let's simplify:
![7x+21 = 105](https://img.qammunity.org/2019/formulas/mathematics/middle-school/ivia9um2bs8l9r32bxtmciir8bveldjqye.png)
Solve for x:
![7x = 84](https://img.qammunity.org/2019/formulas/mathematics/middle-school/u9tsn3sj1mgrtvvojyo4nhvzwhw4n50no5.png)
![x = 12](https://img.qammunity.org/2019/formulas/mathematics/high-school/g45lafny9nnk0qyrciolhx4928w64esywc.png)
That's the first number which means the numbers are the 7 numbers which follow: 12, 13, 14, 15, 16, 17, 18.
To check, sum of those is:
![12+13+14+15+16+17+18 = 105](https://img.qammunity.org/2019/formulas/mathematics/middle-school/pfug74m4t5pb5p3univu40hzi8moelefp3.png)
So, it all works out! Your answer is: 12, 13, 14, 15, 16, 17, 18.