Question

Easy Bucks... 
For what values of y does the binomial 3y−5 belong to the interval (−1; 1)?

Answer 1

`y\in((4)/(3),2`)

Explanation:

We are given that a binomial

`3y-5`

We have to find the value of y for which binomial belongs to the interval (-1,1).

In order to find the value of y we will substitute binomial equal to zero.

`3y-5=0`

`3y=5`

`y=(5)/(3)`

When we substitute
`y=(5)/(3)` then binomial belongs to given interval because 0 lies between -1 and 1.

If substitute
`3y-5=-1`

Then, we get
`3y=-1+5=4`

`y=(4)/(3)`

When we substitute
`3y-5=1` then we get

`3y=1+5=6`

`y=(6)/(3)=2`

If the value of y lies between
`(4)/(3)` and 2 then the binomial belongs to interval (-1,1).

Answer 2

3y-5 = -1

3y=4

y = 4/3

3y-5 = 1

3y = 6

y = 2

y must be between 4/3 and 2

y must be between 1 1/3 and 2