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Find Tan Θ given sin Θ = √3/2 and cos Θ = 1/2 a √3 b 3 c 2 d 4

User Helt
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2 Answers

6 votes

tan theta = sin theta/ cos theta

tan theta = sqrt (3)/2 divided by 1/2

= sqrt (3)/2 * 2/1

sqrt(3)

User Greg Robertson
by
8.8k points
3 votes

We know:


\tan\Theta=(\sin\Theta)/(\cos\Theta)

We have:


\sin\Theta=(\sqrt3)/(2),\ \cos\Theta=(1)/(2)

Substitute:


\tan\Theta=((\sqrt3)/(2))/((1)/(2))=(\sqrt3)/(2):(1)/(2)=(\sqrt3)/(2)\cdot(2)/(1)=\sqrt3

Answer: a. √3

User Richyen
by
8.4k points

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