Question

what is -1/2+1/3 , -3 1/5+(-6 1/2) , 5/8-(-2/8) , -9/10-2/5 , 6 3/5-(-2 1/5) answer all in sum or difference

Answer 1

Explanation:

1.
`(-1)/(2) + (1)/(3)`

We solve it by taking LCM (-3 + 2) / (3 x 6) = 1/6

2.
`-3(1)/(5) + (-6(1)/(2) )`

By taking LCM:

-3 1/5 = (-3 x 5 + 1) / 5 = -16/5

-6 1/2 = - (6 x 2 +1) / 2 = -13/2

Subtracting these values:

-16/5 + (-13/2) = -97/10

3.
`(5)/(8) - (-(2)/(8) )`

Adding the fraction to get: 5/8 + 2/8 = 7/8

4.
`-(9)/(10) - (2)/(5)`

Taking the LCM:

(-9 - 4) / 10 = 13/10

5.
`6(3)/(5) - (-2(1)/(5) )`

Taking the LCM to get:

33/5 + 11/5 = 22/5

Answer 2

Part a)
`-(1)/(2) +(1)/(3)`

`-(1)/(2) +(1)/(3)=(-3+2)/((3*2)) =-(1)/(6)`

the answer Part a) is

`-(1)/(6)`

Part b)
`-3(1)/(5) +(-6(1)/(2) )`

we know that

`-3(1)/(5)=-(3*5+1)/(5)=- (16)/(5)`

`-6(1)/(2)=-(6*2+1)/(2)=- (13)/(2)`

substitute

`- (16)/(5)-(13)/(2)=(-32-65)/(10) =-(97)/(10)`

therefore

the answer part b) is

`-(97)/(10)`

Part c)
`(5)/(8)-(- (2)/(8))`

`(5)/(8)-(- (2)/(8))=(5)/(8)+ (2)/(8)=(7)/(8)`

therefore

the answer part c) is

`(7)/(8)`

Part d)
`-(9)/(10)- (2)/(5)`

`-(9)/(10)- (2)/(5) =(-9-4)/(10)=- (13)/(10)`

therefore

the answer part d) is

`- (13)/(10)`

Part e)
`6(3)/(5)-(2(1)/(5))`

we know that

`6(3)/(5)=(6*5+3)/(5)=(33)/(5)`

`2(1)/(5)=(2*5+1)/(5)=(11)/(5)`

substitute

`(33)/(5)-(11)/(5)=(22)/(5)`

therefore

the answer Part e) is

`(22)/(5)`