74.7k views
5 votes
If m^2 + n^2 = 18 and mn=7, what is (m-n)^2

User Herobrine
by
7.6k points

2 Answers

3 votes

(m-n)^2 = m^2 - 2mn + n^2

(m-n)^2 = m^2 + n^2 - 2mn

Substitute m^2 + n^2 = 18 and mn=7

(m-n)^2 =18 - 2(7)

(m-n)^2 = 18 - 14

(m-n)^2 = 4

User Mdtuyen
by
7.9k points
2 votes

Answer:

(m - n)^2 = 4

Explanation:

(m - n) ^2 = m^2 - 2mn + n^2 when (m-n)^2 is expanded using foil.

But m^2 + n^2 = 18 Given

mn = 7 Given

(m - n)^2 = m^2 + n^2 - 2 mn Substitute in the given values

(m - n)^2= 18 - 2*7 Reduce

(m - n)^2 = 18 - 14 Combine

(m - n)^2 = 4

User Spekdrum
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories