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If m^2 + n^2 = 18 and mn=7, what is (m-n)^2

User Herobrine
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2 Answers

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(m-n)^2 = m^2 - 2mn + n^2

(m-n)^2 = m^2 + n^2 - 2mn

Substitute m^2 + n^2 = 18 and mn=7

(m-n)^2 =18 - 2(7)

(m-n)^2 = 18 - 14

(m-n)^2 = 4

User Mdtuyen
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2 votes

Answer:

(m - n)^2 = 4

Explanation:

(m - n) ^2 = m^2 - 2mn + n^2 when (m-n)^2 is expanded using foil.

But m^2 + n^2 = 18 Given

mn = 7 Given

(m - n)^2 = m^2 + n^2 - 2 mn Substitute in the given values

(m - n)^2= 18 - 2*7 Reduce

(m - n)^2 = 18 - 14 Combine

(m - n)^2 = 4

User Spekdrum
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