y-2 = 3(x+7) put it in y=mx+b form (slope intercept)
y-2 = 3(x+7) distribute 3
y-2 = 3x+21 add 2 to both sides
+2 +2
y = 3x + 23
so now the slope of that is 3 so the new equation has a slope of 3 because parallel slopes are equal.
my new line has a slope of 3 and point (4,2)
so we use point slope formula y-y1 = m(x-x1)
y-2 =3(x-4) put it in y=mx+b form (slope intercept)
y-2 = 3(x-4) distribute 3
y-2 = 3x -12 add 2 to both sides
+2 +2
y = 3x + 10 which is you line slope intercept with parallel slope and contains (4,2)