Question

How many moles of s are needed to combine with 0.208 mol al to give al2s3?

Answer 1

Given, moles of Al = 0.208

Balanced equation for the given chemical reaction:

2Al + 3S --> Al₂S₃

The molar ratio between Al and S is 2:3

0.208 moles of Al x (3 moles of S / 2 moles of Al)

= 0.312 moles of S

Therefore, 0.312 moles of S are needed to combine with 0.208 mol Al to give Al₂S₃

Answer 2

0.312 mol of S

Solution:

The Balance Chemical equation is as follow,

2 Al + 3 S → Al₂S₃

According to this equation,

2 moles of Al required = 3 moles of S

Then,

0.208 moles of Al will require = X moles of S

Solving for X,

X = (0.208 mol × 3 mol) ÷ 2 mol

X = 0.312 mol of S

Result:

0.312 moles of S are needed to combine with 0.208 mol Al to give Al₂S₃.