The structural formula of (2E,4E)-1-chloro-3-methyl-2,4-hexadiene is attached below. The structure was made in following steps.
Step 1:
First of all the parent chain was identified. As the name ends with -hexadiene, it means the parent chain contains 6 carbon atoms along with two double bonds.
Step 2:
Secondly, the position of double bonds was spotted. As the parent name was followed by 2,4- it means the double bonds are present at position 2 and 4.
Step 3:
After that, the positions of substiyuents was measured. As specified in name methyl is present at position 3 and chlorine atom is present at position 1.
Step 4:
At last, the stereochemistry about the double bond was drawn. As E specifies trans positions hence, both double bonds were maade trans.