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What molality of pentane is obtained by dissolving 15 g pentane, c5h12, in 245.0 g hexane, c6h14?

What molality of pentane is obtained by dissolving 15 g pentane, c5h12, in 245.0 g hexane, c6h14?
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What molality of pentane is obtained by dissolving 15 g pentane, c5h12, in 245.0 g hexane, c6h14?

User Linbo
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1 Answer

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Answer

  • The molality of pentane will be be 0.84 Molality

Data given

  • mass of pentane = 15g
  • molar mass of pentane = 72.15
  • mass of solvent (hexane) = 245.0 g = 0.245 Kg

Solution

  • Molality = (given mass ÷ molar mass ) ÷ 1 Kg of solvent
  • Molality = ( 15 ÷ 72.15 ) ÷ 0.245 Kg
  • Molality = 0.84
User Jabavu Adams
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